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Argh, bugs are annoying. The software kind that is.
So I've got a lot on my plate for the week. There's all that car stuff, and then there's the patrol stuff, fund raising stuff, money saving stuff, and money making stuff. Man, I'm hungry now.
Wednesday, October 16, 2024 @ 12:22:45 (UTC)
Wednesday, October 16, 2024 @ 08:22:45 EDT
"The opposite of the religious fanatic is not the fanatical atheist but the gentle cynic who cares not whether there is a god or not."
Eric Hoffer (From The Quotations Page.)
Wednesday, March 26, 2003 at 21:48:12 (UTC)
i need unix help!
i have a seemingly simple task i want to do on unix. I have several files, the names of which represent group names. Each file contains a list of the names of everybody in that group. All I want to do is output a list with everybody's name in one column and the group they belong to in the second column.
How can I do this with a shell script? Any ideas would be mucho appreciated! I am attempting to use a combination of cat, ls, and awk in my script but i can't figure out a way of doing it. temporary files are ok. go ahead and use grep or sed or anything you can use on unix! but no perl.
girl
Monday, March 31, 2003 at 05:24:24 (UTC)
Use awk to get the names out with the current and just pop it to a file. Something like { print FILENAME $1 }
A Concerned Citizen
Monday, March 31, 2003 at 05:25:43 (UTC)
{print FILENAME $0 } would be better for your case.
A Concerned Citizen
Monday, March 31, 2003 at 18:05:11 (UTC)
hey that FILENAME option is really handy.. i should have read the man page! thanks CC
girl