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Hey, it seems as if those university kids (kids, ha!) are finishing up their exams now. I've been getting e-mail from a whole bunch of gals who I haven't heard from in many, many moons. *sigh* Just as I was clearning out my inbox too.
This morning I was supposed to show up early to watch over the office, but I got here and found out that I was locked out! Argh! How come every time I get to work early, nobody is ever in?!? This is the reason why I never get in on time! *shakes fist*
Tuesday, April 23, 2002 at 21:48:00 (UTC)
hey got a physics question:
You've got a 4kg solid ball on the surface of a frictionless table. There is a tiny hole in the middle of the table, through which a cord is threaded. The cord is attached to the ball so that the ball can move with circular motion around the centre of the table. The ball is 1m from the centre of the table (i.e. radius of motion, R, is 1m) and moving with constant velocity 2m/s. Now suppose that the cord is being pulled down through the hole in the table at a constant rate of 0.5 m/s.
1) When R has reached 0.5m, what was the work done?
2) Determine R when the ball has a speed of 9.2m/s
3) What is the time needed for the ball to reach 9.2m/s
girl
Tuesday, April 23, 2002 at 22:26:07 (UTC)
why?
Lazarius <e-mail>
Wednesday, April 24, 2002 at 17:49:21 (UTC)
i was tutoring a first year student and i couldn't answer this question!! (no solution available)
girl
Wednesday, April 24, 2002 at 17:52:20 (UTC)
Okay so if there is conservation of angular momentum why isn't your answer for b) (2m/s)(1m)/(9.2m/s) = 0.217m ? What else are you doing there? How did you get the work done?
girl
Wednesday, April 24, 2002 at 18:19:39 (UTC)
Oops..
I forgot to take a square root and that threw my answer off. (Stupid windows calculator.) I'll throw up my solution later today.
QYV
Saturday, April 27, 2002 at 19:51:32 (UTC)
Assume a sperical cow of uniform density...
llamatron duz physics